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## Homework Statement

If a satellite is to orbit Earth at an altitude of 1.00x10^3 Km, what would be its orbital period? rs = 1.00x10^3 km, Mearth = 5.97x10^24 kg, Gravitational Constant = 6.67x10^-11## Homework Equations

T= 2∏√r^3/GM

## The Attempt at a Solution

rs = 0.815484549m (i converted the satellite's altitude to meters) T= 2∏√0.815484549^3/6.67x10^-11 x 5.97x10^24 = error in my calculator ):Edit: i did not convert km into meters correctly so it would be 1 meter

2∏√1^3/6.67x10^-11 x 5.97x10^24

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