1. The problem statement, all variables and given/known data Find the points on the graph of y = x3ex where the tangent line is horizontal. (Your answer should include x-values and y-values) 2. Relevant equations Product rule fg'+gf' 3. The attempt at a solution (x3)(ex)+(ex)(3x2) x3ex+3x2ex= y' x3ex+3x2ex= 0 x2ex(x+3) = 0 x = -3 Going back to original equation, and plugging in x: y = -33e-3 y = -27e-3 y ≈-1.34 Not sure if I did this correctly.