Find the pressure p_1 due to a single particle

1. Apr 26, 2005

~angel~

Find the pressure p_1 due to a single particle. Express the pressure due to a single particle in terms of k_B, T, L_x, L_y, L_z, and any other given quantities.

I tried using pV=N(k_b)T, but it is wrong.

Thank you.

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2. Apr 26, 2005

whozum

Care to define those variables?

3. Apr 26, 2005

~angel~

k_B is boltzmanns constant. If you look at the picture, you can see that L_x, L_y, and L_z are the length, width and height of the rectangular prism. T is the absolute temperature.

4. Apr 26, 2005

whozum

You can express V in terms of L_x, L_y, L_z
Is this mastering physics?

p = kT/V

No moles here, single particle.

5. Apr 26, 2005

~angel~

Yeah, mastering physics. That's what stuffed me up- the moles. Thanks.

6. Apr 26, 2005

~angel~

Ok...I've now found the pressure for that, and I also found the pressure fon the wall due to a single particle whose squared speed in the x direction is v_x^2 [the answer to the later is (m*v_x)/V]. Now I need to find the pressure in terms of T, k and V, and any other given quantities, but I can't seem to get it.

7. Apr 26, 2005

whozum

Show me your work for finding the pressure for v_x, and v_x^2.

8. Apr 26, 2005

~angel~

p = F/A

The force is equal to dp(momentum)/dt = (2mv_x)/((2*L_x)/(v_x))

Area = Ly*Lz

Therefore, p = (m*v_x)/V