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Introductory Physics Homework Help
Find the rate of change of velocity
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[QUOTE="haruspex, post: 6334024, member: 334404"] "The equation" for the trajectory would just be y as a quadratic function of x. If you differentiate that (with respect to x) it will give you the gradient at any particular point but will not give you a velocity. If you mean the trajectory in parametric form, with time as the parameter, that will be two equations: y as a quadratic in t and x as a linear function of t. Differentiating those with respect to time will give you velocities. This has little to do with the total displacement shown by your blue line, nor with the total time you calculated. I struggle to understand what you are trying to do. Neither do I understand why you would want to "derive" (differentiate) the trajectory with respect to time. The velocity equations are easily obtained directly: v[SUB]x[/SUB](t)=Vcos(θ), v[SUB]y[/SUB](t)=Vsin(θ)-gt. [/QUOTE]
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Introductory Physics Homework Help
Find the rate of change of velocity
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