- #1
BloodPhoenix
- 3
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Find the resisitance of the winding at 20 and 60 degrees.
Information given:
mass: 33.212kg
Dimensons are: L=551.9291667mm
W=48mm
h=144mm
Volume: 3814934.4mm3
Number of turns in the winding: 675 diameter of wire = 2.00mm
The turns can be assumed to be uniformly layered and evenly distributed across the section of the coil. All inter=conducter space is occupied by the insulation and the completed winding can be assumed to fill the winding space.
The winding material has the following parameters at 20C
Density: 8740kg/m3
Resistivity: 1.870E-08ohmM
If anyone can point me in the direction of the equation(s) i would need to use or just show how u got to the answer i would greatly appreciated :D everyone in the module has been totally stumped on this question so please make me be the first with the correct answer :D
Ty all!
Andrew
Information given:
mass: 33.212kg
Dimensons are: L=551.9291667mm
W=48mm
h=144mm
Volume: 3814934.4mm3
Number of turns in the winding: 675 diameter of wire = 2.00mm
The turns can be assumed to be uniformly layered and evenly distributed across the section of the coil. All inter=conducter space is occupied by the insulation and the completed winding can be assumed to fill the winding space.
The winding material has the following parameters at 20C
Density: 8740kg/m3
Resistivity: 1.870E-08ohmM
If anyone can point me in the direction of the equation(s) i would need to use or just show how u got to the answer i would greatly appreciated :D everyone in the module has been totally stumped on this question so please make me be the first with the correct answer :D
Ty all!
Andrew