Find the speed of the ball after the ball leaves the bat

In summary, the problem involves a ball being hit by a bat with a speed of 40 meters/sec and a mass of .14 grams. The bat does 70 Joules of work on the ball and it reaches a height of 25 meters above the point of impact. The task is to find the speed of the ball after it leaves the bat, using the Conservation of Energy principle. The mass of the baseball, gravitational acceleration and height reached are needed for the calculation. The acceleration due to gravity is 9.8ms^2 and the height reached is 26.2m.
  • #1
Le
Hi,
Would you please help me with this problem.
A batter hits a baseball 1.2 meters above the ground (the point of impact). The ball has mass m = .14g
Speed V(initital) before the ball hit the bat is 40 meters/sec. The bat does 70 Joules of work on the ball in hitting it. Find the speed of the ball after the ball leaves the bat. The ball reaches a height of 25 meters above the point of impact.
Thank you,
Le
 
Physics news on Phys.org
  • #2
Speed V(initital) before the ball hit the bat is 40 meters/sec.

In which direction? Down, I presume? And also, I assume that air resistance is negligible.

From the data given, I just need the mass of the baseball, the gravitational acceleration, and the height it reached. Then, just use the Conservation of Energy. The part before the ball being whacked by the bat is not important at all.
 
  • #3
[/quote]The part before the ball being whacked by the bat is not important at all.[/quote]

Yes, it is. The problem says " The bat does 70 Joules of work on the ball in hitting it." and so ADDS 70 Joules to the kinetic energy the ball already had. You use the speed of the ball before the hitting the bat to find its kinetic energy then and add 70 Joules.
 
  • #4
Originally posted by Pandemonium
I just need the mass of the baseball, the gravitational acceleration, and the height it reached.
Isn't acceleration due to gravity 9.8ms^2?

And he says that the mass is .14kg and the height reached is 25m + 1.2m
 

1. What is the formula for finding the speed of the ball after it leaves the bat?

The formula for finding the speed of the ball after it leaves the bat is speed = distance/time. This means that the speed of the ball can be calculated by dividing the distance it travels by the time it takes to cover that distance.

2. How do you measure the distance the ball travels?

The distance the ball travels can be measured using a measuring tape or by marking the starting and ending points and measuring the distance between them. Another way is to use a radar gun, which measures the speed of the ball as it travels and can also calculate the distance based on that speed.

3. Can the speed of the ball vary depending on the type of bat used?

Yes, the speed of the ball can vary depending on the type of bat used. Different bats have different weight, shape, and material, which can affect the force and angle at which the ball is hit, thus impacting its speed.

4. How do factors such as air resistance and wind affect the speed of the ball?

Air resistance and wind can affect the speed of the ball by creating drag, which can slow down the ball. Wind can also change the direction of the ball, altering its speed and trajectory. The force and direction of the wind should be taken into consideration when calculating the speed of the ball.

5. Is it possible to calculate the exact speed of the ball after it leaves the bat?

It is possible to calculate the approximate speed of the ball after it leaves the bat, but it is difficult to determine the exact speed due to various factors such as air resistance, wind, and the angle at which the ball is hit. However, using advanced technology and precise measurements, scientists can get very close to the actual speed of the ball.

Similar threads

  • Introductory Physics Homework Help
Replies
10
Views
1K
  • Introductory Physics Homework Help
Replies
34
Views
594
  • Introductory Physics Homework Help
2
Replies
38
Views
1K
  • Introductory Physics Homework Help
Replies
7
Views
1K
  • Introductory Physics Homework Help
Replies
1
Views
1K
  • Introductory Physics Homework Help
Replies
9
Views
1K
  • Introductory Physics Homework Help
Replies
5
Views
1K
  • Introductory Physics Homework Help
Replies
9
Views
2K
  • Introductory Physics Homework Help
Replies
10
Views
3K
  • Introductory Physics Homework Help
Replies
10
Views
4K
Back
Top