Find the sum

  • Thread starter razored
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  • #1
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[tex]\Sigma_{n=1}^{ \infty} \frac{1}{(3n-2)(3n+1)} [/tex] I simplified it to partial fractions to (1/3) / (3n-2) - (1/3) / (3n+1) Now what?
 

Answers and Replies

  • #2
Dick
Science Advisor
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An infinite number of terms cancel and a finite number of terms don't. Figure out which ones don't. Start writing out terms in the partial fraction expansion for n=1,2,3,4,5... if you need to. You should see the pattern pretty quickly.
 

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