Find the the axial-force in the member BC

  • Thread starter TSN79
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  • #1
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I've come across a problem I can't solve, and I'm hoping you can help me out here...I've got this setup you can see in the drawing. I'm supposed to find the the axial-force in the member BC. I don't even know where to begin...the answer is supposed to be [tex]G-\sqrt{G^2-GF}[/tex]
Anyone...?
 

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  • #2
brewnog
Science Advisor
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It always helps to start these problems by drawing a free body diagram.

Draw one for the bar, and mark on it all forces. You should then be able to start resolving the forces, parallel and perpendicular to the bar.

See how you get on.
 
  • #3
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the big problem is there is no angle given - and probably not necessary - because the system will adjust itself for a suitable equilibrium- the pulleys are smooth.

this is difficult. can anyone do it?
 
  • #4
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how on earth can we determine the angles? ????????
 

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