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please help me if you can the question in this link .

i try many many times but i don't know how i can solve thevenin equivalent with dependent sources.

tomorrow i have a home quiz on this question.

http://imageupload.org/?d=49E036571

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- Thread starter Master Key
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In summary, the conversation is about solving a tricky Thevenin equivalent circuit with dependent sources. The suggestion is to add a test current supply at the output to determine the input voltage V, and then use that to find the Thevenin resistance. Placing a load resistor at a-b can also help find an expression for the power through R. The conversation ends with the suggestion to stick a load resistor on the output and solve for the voltage to pick out the Thevenin voltage and resistance.

- #1

- 2

- 0

please help me if you can the question in this link .

i try many many times but i don't know how i can solve thevenin equivalent with dependent sources.

tomorrow i have a home quiz on this question.

http://imageupload.org/?d=49E036571

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- #2

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This is a tricky one, as the Thevenin resistance of the circuit will be load dependent.

I suggest that you add a 'test' current supply at the output and determine what the input voltage V will be. The Thevenin resistance will be V/I. You'll find that V and V/I depend upon the value of the test current.

If a load resistor R is placed at a-b, then the current through it will V/R. You should be able to use this fact with the expression that you found for the output voltage to find an expression for the power through R.

EDIT: Perhaps I was too hasty in my evaluation. If you just stick a load resistor on the output and solve for the voltage that appears across it, the form of the resulting expression should look very familiar. You should be able to pick the Thevenin voltage and resistance out of it by inspection!

I suggest that you add a 'test' current supply at the output and determine what the input voltage V will be. The Thevenin resistance will be V/I. You'll find that V and V/I depend upon the value of the test current.

If a load resistor R is placed at a-b, then the current through it will V/R. You should be able to use this fact with the expression that you found for the output voltage to find an expression for the power through R.

EDIT: Perhaps I was too hasty in my evaluation. If you just stick a load resistor on the output and solve for the voltage that appears across it, the form of the resulting expression should look very familiar. You should be able to pick the Thevenin voltage and resistance out of it by inspection!

Last edited:

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thanks alot

A Thevenin equivalent is a simplified circuit model that represents a complex circuit with a single voltage source and resistance.

Finding the Thevenin equivalent is important because it allows us to analyze and understand the behavior of a complex circuit without having to deal with its intricate details.

The Thevenin equivalent is calculated by removing a load from the circuit and finding the equivalent voltage and resistance at the load's terminals.

The advantages of using the Thevenin equivalent include simplifying circuit analysis, predicting circuit behavior, and facilitating circuit design and troubleshooting.

No, the Thevenin equivalent can only be used for linear circuits, meaning circuits with linear elements such as resistors, capacitors, and inductors.

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