This question comes from my Grade 11 Univ. Physics Teacher. Problem: To as many significant figures as you can justify, determine the thickness of the aluminium foil. 1. Purpose 2. Procedure 3. Calculations (Significant Figures) 4. Conclucion Now I know that the density of Aluminium is 2.7g/cm^3. And I also know that the formula for cm^3 is Length X Width X Thickness. So if i find the mass, multiply it by the density, and divide it by the length and the width, will I come out with the thickness? He said there are many ways to do this and this is the only one I could come up with so any input or help would be much appreciated. Regards; Patrick
I am not a physicist but the answer seems to be yes. As a check-up, you can submerge it in water and measure displacement. Then work backwards from volume to thickness. If you perform both methods, then you can have a range (low estimate and high estimate).
This was my first idea, but then he said there are many other ways so I was hoping to think of something to do that others would not.
Measure the foil length and width and then place it into a full measuring cylinder and collect the displaced water. You now have the volume of foil, the length and width and so can find thickness
density=mass/volume, so volume = mass/density, not density*mass. Though you'll need a very accurate scale or a sizeable amount of foil to measure the mass accurately.
Well I just measured the foil and I came out with 2.7 grams. Here is what I have so far: Lenth: 30cm Width: 21cm Mass: 2.7g Density: 2.7g/cm^3. Am I missing any vital information? Im sorry to ask for help with it comes to the forumla and such, but I'm really stuck on this one, been working on it for 2 days :P I was told that you calculate the Area, (Length*Width*Height), then multiply together the Mass and the Density. Ahh, I'm so confussled :( *I got it. Thanks to all that helped, much appreciated :)*