1. The problem statement, all variables and given/known data A particle is thrown in the angle pi/3 radian with speed 10m/S. Find the time of movement if the maximal height is equal to the distance of fall. 2. Relevant equations v^2-voy^2=2gh 3. The attempt at a solution 0-10^2*3/4=2*10*hmax hmax=3.75 v0x*2t=3.75 v0*cos60*2t=3.75 10*0.5*2*t=3.75 t=0.375. The answer in my book is 1S. I also want to know why whe I use the formula of maximal height v0^2sin^a/2g and maximal fallL=v0^2sin2a/g with the data from the problem they don't come out to be equal.