Find the time required for the boat to slow to 45 km/hr

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In summary, the conversation discusses a boat traveling at 90km/h with an engine shut off and the frictional force between the boat and water. The frictional force is proportional to the boat's speed and can be calculated using a formula. The conversation also mentions finding the time required for the boat to slow to 45 km/h and suggests using the Newton's law and integrating the ODE to solve for time. The final result is t=(\frac{1000}{70}\ln 2) s.
  • #1
king_naeem
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hey

A 1000 kg boat is traveling at 90km/h when its engine is shut off. The magnitude of the frictional force between boat and water is proportional to the speed v of the boat: force of kinetic fricition=70v, where v is in meters per second and the force is in Newtons. Find the time required for the boat to slow to 45 km/hr
 
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  • #2
king_naeem said:
hey

A 1000 kg boat is traveling at 90km/h when its engine is shut off. The magnitude of the frictional force between boat and water is proportional to the speed v of the boat: force of kinetic fricition=70v, where v is in meters per second and the force is in Newtons. Find the time required for the boat to slow to 45 km/hr

I'm a theorist,so i'll let u plug the numbers:
The Newton's law states:[itex] m\frac{dv}{dt}=-\alpha v [/itex],where alpha is that 70 in your problem:
Integrate the ODE wrt to proper limits:
Final result:[itex] t=(\frac{1000}{70}\ln 2) s [/itex]

Good luck!
 
  • #3
.

To find the time required for the boat to slow to 45 km/hr, we can use the formula for acceleration: a = F/m, where a is the acceleration, F is the net force, and m is the mass of the boat. In this case, the net force is the frictional force, which is given by 70v. We can also convert the speed of the boat from km/hr to m/s by multiplying it by 1000/3600 (since 1 km/hr = 1000/3600 m/s). So, the speed of the boat in m/s is 45 * 1000/3600 = 12.5 m/s.

Now, we can plug in the values into the formula for acceleration:

a = 70 * 12.5 / 1000 = 0.875 m/s^2

Next, we can use the formula for uniform acceleration to find the time required for the boat to slow down from 12.5 m/s to 0 m/s:

v = u + at

Where v is the final velocity (0 m/s), u is the initial velocity (12.5 m/s), a is the acceleration (0.875 m/s^2) and t is the time we are looking for. Rearranging the equation to solve for t, we get:

t = (v-u)/a = (0 - 12.5)/0.875 = -14.29 seconds

However, we cannot have a negative time, so we can conclude that it will take approximately 14.29 seconds for the boat to slow down from 90 km/hr to 45 km/hr.
 

1. What is the formula for finding the time required for the boat to slow down?

The formula for finding the time required for the boat to slow down is t = (v - u) / a, where t is the time, v is the final velocity, u is the initial velocity, and a is the acceleration.

2. How do I determine the final velocity of the boat?

The final velocity of the boat can be determined by using a basic physics formula, v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time required for the boat to slow down.

3. What units should I use for the velocity and acceleration in the formula?

The units for velocity and acceleration should be consistent. This means that if the velocity is in km/hr, then the acceleration should also be in km/hr. It is important to convert the units if necessary before plugging them into the formula.

4. Can I use this formula for any type of boat and situation?

Yes, this formula can be used for any type of boat and situation as long as the initial and final velocities and the acceleration are known. However, it is important to note that this formula assumes constant acceleration, which may not always be the case in real-life situations.

5. Is this formula accurate for calculating the time required for the boat to slow down?

This formula provides a good estimate for the time required for the boat to slow down, but it may not be completely accurate due to factors such as air resistance, water currents, and other external forces. It is always best to consider these factors and make adjustments to the formula if necessary.

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