Find the value of A^2

Member warned about posting without the homework template
please check the attachment below. The question and the attempted solution is found there. Thanks a lot for your help in advance.

Attachments

• calculusproblem.jpg
36.1 KB · Views: 396

HallsofIvy
Homework Helper
I have great difficulty reading this but it appears that you are integrating the function A (sin(2pi/L) x from 0 to L. That a rather trivial integral. Are you sure it isn't A sin((2pi/L) x)= A sin(2pi x/L)?

You also have "x" in your final answer. Since this is a definite integral, evaluated for x equal to the limits of integration, there should be no "x" in the result.

Thank you so much hallsoflvy for your reply. I am very grateful! I have attached a new picture to this email. I am looking for the value of A when the function is equal to zero. The final answer is sqrt (2/L). I want to understand the steps and how they got the final answer. Thanks so much in advance!

Attachments

• intergration.jpg
31.6 KB · Views: 379
Ray Vickson
Homework Helper
Dearly Missed
please check the attachment below. The question and the attempted solution is found there. Thanks a lot for your help in advance.

Doing this would also help future readers, in case your picture gets deleted or something.

Hey Ray, please look at the updated attachment below. I have tried to edit the old one but dont see any button that would allow me do so. Thanks so much for your help in advance! :)

Attachments

• intergration.jpg
31.6 KB · Views: 399
Hey Ray, please look at the updated attachment below. I have tried to edit the old one but dont see any button that would allow me do so. Thanks so much for your help in advance! :)

The ##X## is most likely an argument of the function ##\sin##, that is, it should be inside the brackets. Why are you studying quantum mechanics without doing calculus first? You should definitely study calculus before. This is the simplest math you'll encounter.