- Get a vector equation of the line that pass by the point P and intersect with the straight line R and S
- All below.
I think that we can say that PPR = α*PRPS
where PR and PS are the points where occurs the intersection on the line R and S.
Obs: line r and s are found by knowing that the straight line intersection of two planes are
n1 X n2 [cross product]
Lr = (0,1,-2) + y(-1,1,1)
Ls = (0,1,-1) + u(1,2,1)
This leave us to three equation and three incognits
Three real solution, but the answer is that is impossible, why?
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