During the time period t=0 to t=6 seconds, a particle moves along the path given by x(t)=3cos(pi*t) and y(t)=5sin(pi*t) 1. Find the velocity vector for the particle at any time t. 2. Write and evaluate an integral expression, in terms of sine and cosine, that gives distance the particle travels from time t=1.25 to t=1.75. Not quite sure what a velocity vector is... For the second, it looks like an arclength so it would be Integral from 1.25 to 1.75 Sqrt((dy/dt)2 + (dx/dt)^2), so just derive the given (3cos(pi*t), etc. and plug in?