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solve for z... z=sqrt((16-x^2-y^2)/(10))

z = sqrt((16-r^2)/10)

so to find the volume, my integral looks like this:

latex doesnt seem to be working, so this could look messy...

2*int (from 0-2pi)*int(from 0-1)* sqrt((16-r^2)/(10))*r*dr*d(theta)

the 2 in front of the integral is to find the volume, since the integral only gives half of the volume right? is my setup correct? cause i keep getting the wrong answers