A ball of radius 11 has a round hole of radius 8 drilled through its center. Find the volume of the resulting solid(adsbygoogle = window.adsbygoogle || []).push({});

here's what i done:

y = sqrt(11^2-x^2)

y = 8 about x-axis

[tex]\int pi*(8)^2 - pi*(8-sqrt(11^2-x^2))[/tex]

this is where im stuck at, no clue if my setup is even correct. What would the bounds be and is my setup correct?

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# Homework Help: Find the volume of the resulting solid

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