I'm pretty lost with this problem. Can someone please help me with this question? Thanks!! Find the volume of the solid generated by revolving the region about the given line The region in the first quadrant bounded above by the line y=1, below by the curve y=√(sin6x), and on the left by the y-axis, about the line y=1 a) pi/6 + 6 b)pi/12 - 1/6 c)pi^2/12 - pi/6 d)pi^2/12 + pi/6 I set up two possible integrals V=pi∫((arcsin y^2)/6)^2 dy from y=0 to y=1 V=pi∫(√ (sin6x))^2 dx from x=0 to x=pi Im not getting any of the possible answers and I dont know what else to do. Please help!