I'm pretty lost with this problem. Can someone please help me with this question? Thanks!!(adsbygoogle = window.adsbygoogle || []).push({});

Find the volume of the solid generated by revolving the region about the given line

The region in the first quadrant bounded above by the line y=1, below by the curve y=√(sin6x), and on the left by the y-axis, about the line y=1

a) pi/6 + 6

b)pi/12 - 1/6

c)pi^2/12 - pi/6

d)pi^2/12 + pi/6

I set up two possible integrals

V=pi∫((arcsin y^2)/6)^2 dy from y=0 to y=1

V=pi∫(√ (sin6x))^2 dx from x=0 to x=pi

Im not getting any of the possible answers and I dont know what else to do. Please help!

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# Find the volume

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