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ThePhysicsXV
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Homework Statement
What is the wavelength of an 8cm closed pipe when it is sounding the 7th harmonic?
Homework Equations
L=λn/4
The Attempt at a Solution
L=(.08m*7)/(4)
L=0.14m
Am I correct?
ThePhysicsXV said:L=(.08m*7)/(4)
L=0.14m
Am I correct?
Wavelengthdrvrm said:check your calculation-are you finding out the pipe length or wavelength?
Oh yeah wavelength, so isdrvrm said:check your calculation-are you finding out the pipe length or wavelength?
I think its correct!ThePhysicsXV said:Oh yeah wavelength, so is
λ=4L/n
λ=4(.08)/7
Since is 7th harmonic.
λ= .045m
The formula for finding the wavelength of an 8cm closed pipe at the 7th harmonic is λ = 4L/7, where λ is the wavelength and L is the length of the pipe.
A closed pipe means that both ends of the pipe are sealed, whereas an open pipe means that one end is open and the other is closed. In this case, the pipe is closed since we are looking at the 7th harmonic.
This formula can be used for any closed pipe, regardless of its length. However, the length of the pipe will affect the wavelength value.
The 7th harmonic is used because it is the first harmonic that produces a full standing wave in a closed pipe. This means that there are 7 nodes and 8 anti-nodes, resulting in a wavelength that is equal to 4 times the length of the pipe.
You can verify the accuracy of your calculated wavelength by comparing it to the wavelength of the 7th harmonic in the harmonic series. This value should be equal to the calculated wavelength using the formula mentioned above.