You are given vectors a = 4.50i-7.00j and b = -3.50i+7.40j. A third vector c lies in the xy-plane. Vector c is perpendicular to vector a and the scalar product of c with b is 10.0. now i figured that since vector a is in quad 4, then to be perpendicular, vector c would have to be in quad 1 or 3, but im not sure which one. i got that to find the scalar product, its 10 = -3.5(Xc)+7.4(1.556Yc) & arctan(32.7352)=Xc/1.556Yc. but then i kind of reach a dead end and i can't figure out what to do. the question asks to find the x and y component of vector c.