- #1
P-Illiterate
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A particle starts from the origin at t = 0 and moves along the positive x axis. A graph of the velocity of the particle as a function of the time is shown in Fig. 2-43;
the v-axis scale is set by vs = 7.00 m/s. (a) What is the coordinate of the particle at t = 5.0 s? (b) What is the velocity of the particle at t = 5.0 s? (c) What is the acceleration of the particle at t = 5.0 s? (d) What is the average velocity of the particle between t = 1.0 s and t = 5.0 s? (e) What is the average acceleration of the particle between t = 1.0 s and t = 5.0 s?
Vf= Vi+at
Vavg = (Vf+Vi)/2
a avg= change in v/change in time
I think all my answers are wrong!
a) (2,5) --> Looking at the graph
b) t =5s, v=2 m/s
c) Vf= Vi+at
(4-2)/1 = a
a = 2 m/s
d) Vavg = (Vf+Vi)/2
(2=2)/2
= 2 m/s
e) a avg= change in v/change in time
=0 m/s
the v-axis scale is set by vs = 7.00 m/s. (a) What is the coordinate of the particle at t = 5.0 s? (b) What is the velocity of the particle at t = 5.0 s? (c) What is the acceleration of the particle at t = 5.0 s? (d) What is the average velocity of the particle between t = 1.0 s and t = 5.0 s? (e) What is the average acceleration of the particle between t = 1.0 s and t = 5.0 s?
Homework Equations
Vf= Vi+at
Vavg = (Vf+Vi)/2
a avg= change in v/change in time
The Attempt at a Solution
I think all my answers are wrong!
a) (2,5) --> Looking at the graph
b) t =5s, v=2 m/s
c) Vf= Vi+at
(4-2)/1 = a
a = 2 m/s
d) Vavg = (Vf+Vi)/2
(2=2)/2
= 2 m/s
e) a avg= change in v/change in time
=0 m/s