When a battery is connected to a 110.-ohm resistor, the current is 3.98 A. When the same battery is connected to a 400.-ohm resistor, the current is 1.11 A. Find the emf supplied by the battery and the internal resistance of the battery. Equations: Vemf = i*R I'm not sure how to approach this since you get two voltages (438.7 and 444) from the different resistors. Should I treat these resistors like they are in the same circuit? In series or in parallel? Please help!