1. The problem statement, all variables and given/known data Find voltage between node 1 and node 2 2. Relevant equations What is the algorithm? 3. The attempt at a solution R1=4 Ohms R2=5 Ohms R3=8 Ohms R4=3 Ohms R5=6 Ohms R6=7 Ohms Eэ=20 V E3=17 V E5=15 V
try "balanced wheat stone bridge" you wont need Kirhgoff rules here:http://en.wikipedia.org/wiki/Wheatstone_bridge
You want the voltage between nodes 1 and 2. Use the current you found for the first loop (leftmost) using Kirchhoff to determine the voltage across R1. Then do the obvious voltage sum.
That's not the value I get for i1. Better check your derivation. EDIT: My error. Redoing my sums I see that i1 is indeed about 3.7A.
Very sorry. I see that your figure of 3.7A for i1 and about 5.2V for the voltage between nodes 1 and 2 look okay.
Again, sorry about that. 15 pages of A4? That seems like a lot for just three loops. What method are you using to solve the equations?
It's a big work like coursework.I have 8 exercises need to do with this scheme(different trasformations like triangle-star and different methods of finding currents like method of equivalent generator(I don't know how does it called in English.translate from russian),node voltage method and etc.).And another 7 schemes.One of them is my previous topic's scheme. I got this result(3.7) by different methods.So if it's wrong - all my work is wrong
I see, so this is just one exercise for the given schematic. It seems to me that a KVL loop approach is the most straight forward for this particular question, since you really only need to solve for the current in the first loop. Have you learned the method to directly write (by inspection) the matrix form of the equations? That allows you solve for the currents using a matrix method (such as Cramer's Rule), which takes only a few lines.
if it's cramer's method... I know this method but I only use it in programming.I solve all equtations in MathCAd.And then I show result without numbers and then the final result.The result without numbers is very big sometimes.
Okay, even better. Attached is an example, using MathCad, of solving the loops by writing the loop equations in matrix form (which can be done by inspection, and is (almost) foolproof). It's very quick.
Intersting.I didn't know about it in Mathcad all results are the same as the results in my method of countour currents thank you for your help.