# Find Work thermodynamics

1. Sep 10, 2015

### DottZakapa

A volume VA contains n mole of a bi-atomic ideal gas, initially at temperature TA. Burning an amount M of methane, whose calorific power P (produced heat per unit mass while burning) is 13271 [kcal/kg], the temperature is slowly doubled, simultaneously expanding the volume in order to maintain the ratio (T2 / V) constant. Assuming that no heat is wasted in the environment.
DATA:
n= 0.3 [mole]; R= 0.082 [litre*atm/(mole*K)] ;
VA=9 [litre] ; TA=300 [K]; 1 [cal]=4.18[J]]

Following there is what i've solved so far:
PA=(nRTA)/ VA

TB= 2TA

VB=(TB2⋅VA)/ TA2= 4VA

PB=(nR2TA)/ 4VA

Considering that pressure and temperature aren't constant during the transformation, I'm not sure which value instead of pressure I have to insert in the integral in order to evaluate the work during the transformation.

W=∫ p⋅dV

I guess that I shall use this relation :

T2 / V = TA2 / VA

The solution to this is :

W=∫ p⋅dV=2nRTA

but I don't get how.
Could somebody help me with this?
Thanks

Last edited: Sep 10, 2015
2. Sep 10, 2015

### Staff: Mentor

How are T, V, TA, and VA related?

In terms of TA, VA, and n, what is the initial pressure pA?

What is the pressure when the volume is V?

Chet

3. Sep 10, 2015

### DottZakapa

I've edited the template

4. Sep 10, 2015

### Staff: Mentor

Express p as a function of n, TA, VA and V. Then integrate.

Chet