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Find x(t) given a(t)

  1. Sep 11, 2014 #1
    1. The problem statement, all variables and given/known data

    A particle is accelerated according to a(t) = 3.0t m/s^2. What is the position of the particle if it starts out with v=2.0 m/s and x = 0 at t = 0.


    2. Relevant equations

    s(t)=1/2at^2 + vot + xo


    3. The attempt at a solution

    I took the integral of a(t) to get my v(t), and then took the integral of v(t) to get my x(t). None of my answers match with the given choices.

    The possible answers according to this sheet are:

    (a). x(t) = 3.0t^2 + 2.0t m
    (b). x(t) = 3.0t^3 + 2.0t m
    (c). x(t) = t^3 +2.0t m
     
    Last edited: Sep 11, 2014
  2. jcsd
  3. Sep 11, 2014 #2

    BvU

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    There being no difference whatsoever between answer a and answer b ?

    By the way: what does your answer look like ?
     
  4. Sep 11, 2014 #3

    TSny

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    Note that this equation is not relevant to this problem since the acceleration is not constant in this problem.

    That sounds good.

    I agree that none of these answers is correct.
     
  5. Sep 11, 2014 #4
    Yeah, sorry. I fixed that.

    Nonetheless, the professor seems to have made a mistake on this problem set.

    Thanks guys!
     
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