How can u solve this equation (3^x)-(3^-x)=4

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In summary, the conversation discusses how to solve the equation (3^x)-(3^-x)=4. The suggested method is to multiply both sides by 3^x and then use a substitution of t=3^x to turn the equation into a quadratic form. The conversation also mentions the importance of substituting back in the original variable after solving the quadratic. The participants in the conversation encourage the original poster to show their attempts and give hints rather than solving the equation completely. The original poster expresses gratitude for the help received.
  • #1
rise
2
0
how can u solve this equation (3^x)-(3^-x)=4...hehe:P
please i really need it fast..TT
 
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  • #2
"please i really need it fast."

That's not how it works - you need to show some of your first tries, or explain what you've done that hasn't worked. At that time you may receive hints.
 
  • #3
Hmm.. to get you started, multiply everything by 3^(x).. from there everything is bright and clear.
 
  • #4
then take a substitution of the form [tex] t=3^x[/tex] so u'll get a quadratic eq.
 
  • #5
once you get you solve the quadratic, don't forget to substitute 3x=t back again :smile:
 
  • #6
Guys we've helped enough now let the OP do the math.
 
  • #7
damn!you people are damn good!:P i tried many times but nothing happens..THX GUYS:)
 

What is the equation (3^x)-(3^-x)=4?

The equation (3^x)-(3^-x)=4 is a mathematical expression involving the exponential function and its inverse. It is asking to find the value of x that satisfies the equation.

What is the process for solving this equation?

To solve this equation, we need to use logarithms. We can rewrite the equation as (3^x)/(3^-x)=4 and then take the natural logarithm of both sides. This will allow us to use the properties of logarithms to simplify the equation and solve for x.

Why do we need to use logarithms to solve this equation?

The equation (3^x)-(3^-x)=4 involves exponential terms with different bases, which makes it difficult to solve algebraically. By taking the natural logarithm of both sides, we can use the power and quotient properties of logarithms to simplify the equation and solve for x.

Are there any restrictions on the values of x that can satisfy this equation?

Yes, there are restrictions on the values of x. Since we cannot take the logarithm of a negative number, x cannot be equal to zero or any negative number. Additionally, x cannot be equal to 1 or -1 as these values would result in division by zero.

Can this equation have more than one solution?

Yes, this equation can have more than one solution. Depending on the value of the constant on the right side (in this case, 4), there can be either two or no real solutions. This can be determined by analyzing the graph of the function (3^x)-(3^-x) and its intersection with the horizontal line y=4.

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