Is it possible to eliminate y from the equation y'=e^x/(cos(y)+1)?

  • Thread starter adam199
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In summary, the person is seeking help with eliminating y from the equation y'=e^x/(cos(y)+1). They were able to get the result of y'=e^x/(cos(y)+1), but it is not possible to completely eliminate y from the equation. However, they can find the instantaneous slope at a specific point (x,y) and use it to write an equation for the tangent line at that point.
  • #1
adam199
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Title says it all. I can't seem to eliminate y and put y' in terms of x, if it is even possible at all. After messing around the closest I got was:

y'=e^x/(cos(y)+1)

I would really appreciate the help, especially if someone can tell me if it is possible at all to eliminate y from the equation, and how I can work that out.
 
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  • #2
Hi adam199,

That is the correct result. And no, you cannot eliminate y from the expression.

However, you can take any point (x,y) = (3,4) for example, and plug it into the equation to get the instantaneous slope at that very point. Then you can use that slope to write an equation for the line tangent to y(x) at (3,4).
 

What is the equation "Find y'(x) when sin(y)+y=e^x" asking for?

The equation is asking for the derivative of y with respect to x, or y'(x).

What is the first step in finding the derivative of y in this equation?

The first step is to rewrite the equation in terms of y and x, rather than e^x.

What is the derivative of sin(y) with respect to x?

The derivative of sin(y) with respect to x is cos(y) * y'(x).

What is the derivative of y with respect to x in this equation?

The derivative of y with respect to x is y'(x).

How do you solve for y'(x) in this equation?

To solve for y'(x), you will need to isolate it on one side of the equation and use the chain rule to find the derivative of each term on the other side of the equation.

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