1. The problem statement, all variables and given/known data Find the equation of the plane which contains the line: (x,y,z) = (3,3,-3) + t(0,-3,-3) and is parallel to the line: (x,y,z) = (4,2,0) + t (3,-2,1) Write your answer in the form 2 x + B y + C z = D, and give the values of B, C and D as your answer 2. Relevant equations Cross Product (x-x0, y-y0, z-z0) . (a, b, c) = 0 3. The attempt at a solution So I need a point and a normal to determine the equation of the plane. Point: (3,3,-3). The normal I found was the cross product of (0,-3,-3) and (3,-2,1) = (-9,9,-9). I then used the equation (x-x0, y-y0, z-z0) . (a, b, c) = 0 and got -9x+9y-9z=27. Then i multiplied it by -2/9 since the answer needed to start with 2x, I get 2x-2y+2z=-6 but its wrong.. So any help would be appreciated! Thank You!