Finding a point in a plane.

1. May 7, 2012

hivesaeed4

Consider a general point in a plane $${(x, y, z)}$$ and a specific point $${(x_0, y_0, z_0)}$$. The vector

$${(x - x_0)\tmmathbf{i}+ (y - y_0)\tmmathbf{j}+ (z - z_0)\tmmathbf{k}}$$

is parallel to the plane.

Consider the plane $${{(x, y, z,) |y = z}}$$. One point that lies in the plane is the point $${(1, 1, 1)}$$. Find a second point in the plane and the vector that connects them.

So are the below answers correct?

Second point (2,2,2)
Vector= i+j+k

2. May 7, 2012

mathman

The text is messed up. The line after "The vector" is garbled. "(x−x 0 )\tmmathbfi+(y−y 0 )\tmmathbfj+(z−z 0 )\tmmathbfk"

Also "(x,y,z,)|y=z" is an unusual terminology - what does it mean?

3. May 7, 2012

scurty

He just meant i hat, j hat, and k hat. $\hat{i}, \ \hat{j}, \ \hat{k}$

4. May 7, 2012

hivesaeed4

Thanks for the clarification scurty. Now as for
Also "(x,y,z,)|y=z" is an unusual terminology - what does it mean?

Well honestly I don't know my self but I'm supposing it means any point where y is equal to z.