1. The problem statement, all variables and given/known data Let f be the function f(x) = (x2 - 3)ex for all real #'s x. a. What values of x is f increasing? b. What are the x-coordinates of the inflection points for f? c. Where (by finding the x and y coordinates of a point) is f(x) at its absolute maximum. 2. Relevant equations Product rule: uv' + vu' 3. The attempt at a solution PART A f(x) = (x2 - 3)ex f '(x) = ex(x2 + 2x -3) x = 1 and x = -3 If x < -3, f '(x) is positive which means that f is increasing. Same thing for x > 1 :. f increases when x < -3 and x > 1 PART B This is the part where I encounter trouble. Usually I have no problem with these types of problems ... but I can't find when the second derivative equals zero. f '(x) = ex(x2 + 2x -3) f ''(x) = ex(x2 +4x -1) This is a no-calculator-at-all problem so it has to be relatively easy to find when f ''(x) = 0. Here, it's not. Did I make a mistake somewhere?