A .18 kg block sits against a horizontal spring. A 22 N force is applied by a hand and the spring is compressed .18 m. There is a coefficient of kinetic friction between the table and block of .3. Once the spring is compressed, the force holds the block in place without motion. What is k (spring constant)? Would k = 22 N / .18 m or would k = (22N + friction force) / .18 m? When it's in the compressed state, tendency of motion is toward equilibrium, so do you calculate it with the force applied and friction both acting against the motion of the spring or just the force applied since it's still? No static friction coefficient was given, so I'm confused. The problem before had us do a free-body diagram for the object in the compressed state, and I thought that both the force applied and friction would be acting against it, even though static friction wasn't given, so I did Fspring = -kx = (Fapplied + uFn) and got 125 N/m any ideas if this is correct?