- #1

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Thanks,

hk

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- Thread starter h_k331
- Start date

- #1

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Thanks,

hk

- #2

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\sec \left( {2x} \right)\tan \left( {2x} \right) = \frac{{\sin \left( {2x} \right)}}{{\cos ^2 \left( {2x} \right)}}

[/tex]

You should be able to finish it off.

- #3

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replace 2x by u and you have secu 's derivative under the integral sign

- #4

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Then (1/2)du=sec(2x)tan(2x)dx. I'm not sure if this is the prefered method but it came out to the correct answer.

hk

- #5

HallsofIvy

Science Advisor

Homework Helper

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Looks good to me!

- #6

- 33

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Thank you for the replys.

hk

hk

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