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Finding an antiderivative using substitution rule

  • Thread starter h_k331
  • Start date
33
0
I'm trying to find the antiderivative of [sec(2x)tan(2x)], I can't figure out what part I should be substituting. Any help is appreciated.

Thanks,
hk
 
584
0
[tex]
\sec \left( {2x} \right)\tan \left( {2x} \right) = \frac{{\sin \left( {2x} \right)}}{{\cos ^2 \left( {2x} \right)}}
[/tex]

You should be able to finish it off.
 
111
0
replace 2x by u and you have secu 's derivative under the integral sign
 
33
0
I ended up working on it some more and came up with u=sec(2x).
Then (1/2)du=sec(2x)tan(2x)dx. I'm not sure if this is the prefered method but it came out to the correct answer.

hk
 

HallsofIvy

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Looks good to me!
 
33
0
Thank you for the replys.

hk
 

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