Hello everyone, this problem is very long so if i screw up one part the whole thing is wrong. But i'm pretty sure i'm doing it right...(adsbygoogle = window.adsbygoogle || []).push({});

The last 5 questions asked me to find the tangent of line T1 and T2 to the Curve t1/t2, at the point (1,3,1). So i found everything, and now i have a vector T1 and T2;

T1 = <1+t,3,1+8t>

T2 = <1,3+3t,1-4t>

Now he wants me to find an equation descrbing the plane containing T1 and T2, one way i could do this is to take the cross product of the 2 vectors because they both intersect at the same point, (1,3,1)....but thats not how he wants us to do it, he wants us to use a method with tangent planes and linear approximation but i'm confused on how to do that@! the chaper doesn't talk about that at all...all he says is

We know that any plan passing through the point P(xo,yo,zo) has an eqwuation of the form

A(x-xo) + B(y-yo) + C(z-zo) = 0;

then it says we can rewrite it as z - zo = a(x-xo) + b(y-yo);

Then it says

Suppose f has continous partial derivatives. An equation of the tangent plane to the surface z = f(x,y) at the point P(xo,yo,zo) is

z-zo = fx(xo,yo)(x-xo) + fy(xo,yo)(y-yo);

note: fx means partial derivative with respect of x;

Any ideas on what i could do ? Thanks@

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# Homework Help: Finding an equation describing the plane containing t1&t2?

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