1. Sep 19, 2005 #1

   Stevecgz

   

   I'm attempting to find:
   [tex]\int \cos^2x\tan^3x dx[/tex]
   I've tried substitution and integration by parts but I'm having no success. Can someone help me out on how I get this one started?
   
   Steve

    

   Last edited: Sep 19, 2005

   Stevecgz, Sep 19, 2005
2. 
   Phys.org - latest science and technology news stories on Phys.org

   • • Scarlet macaw DNA points to ancient breeding operation in Southwest
   • • Mathematicians solve age-old spaghetti mystery
   • • New technology can detect hundreds of proteins in a single sample
3. Sep 19, 2005 #2

   dextercioby

   

   Science Advisor

   Homework Helper

   Insights Author

   It's no big deal.
   
   [tex] \int \frac{\sin^{3}x}{\cos x} \ dx =\int \frac{\sin x \left(1-\cos^{2}x\right)}{\cos x} \ dx =\int \tan x \ dx -\int \sin x \ d\left(\sin x\right) = ... [/tex]
   
   Daniel.

    

   dextercioby, Sep 19, 2005
4. Sep 19, 2005 #3

   Stevecgz

   

   Thanks dextercioby, I understand it now.
   
   Steve

    

   Stevecgz, Sep 19, 2005

• Log in with Facebook
• Log in with Twitter

Your name or email address:

Do you already have an account?

• No, create an account now.
• Yes, my password is:
• Forgot your password?

Stay logged in