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Homework Help: Finding an integral

  1. Sep 19, 2005 #1
    I'm attempting to find:
    [tex]\int \cos^2x\tan^3x dx[/tex]
    I've tried substitution and integration by parts but I'm having no success. Can someone help me out on how I get this one started?

    Steve
     
    Last edited: Sep 19, 2005
  2. jcsd
  3. Sep 19, 2005 #2

    dextercioby

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    It's no big deal.

    [tex] \int \frac{\sin^{3}x}{\cos x} \ dx =\int \frac{\sin x \left(1-\cos^{2}x\right)}{\cos x} \ dx =\int \tan x \ dx -\int \sin x \ d\left(\sin x\right) = ... [/tex]

    Daniel.
     
  4. Sep 19, 2005 #3
    Thanks dextercioby, I understand it now.

    Steve
     
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