Finding an integral

  • Thread starter Stevecgz
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  • #1
Stevecgz
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I'm attempting to find:
[tex]\int \cos^2x\tan^3x dx[/tex]
I've tried substitution and integration by parts but I'm having no success. Can someone help me out on how I get this one started?

Steve
 
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Answers and Replies

  • #2
dextercioby
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It's no big deal.

[tex] \int \frac{\sin^{3}x}{\cos x} \ dx =\int \frac{\sin x \left(1-\cos^{2}x\right)}{\cos x} \ dx =\int \tan x \ dx -\int \sin x \ d\left(\sin x\right) = ... [/tex]

Daniel.
 
  • #3
Stevecgz
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Thanks dextercioby, I understand it now.

Steve
 

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