1. Sep 19, 2005 #1

   Stevecgz

   

   I'm attempting to find:
   [tex]\int \cos^2x\tan^3x dx[/tex]
   I've tried substitution and integration by parts but I'm having no success. Can someone help me out on how I get this one started?
   
   Steve

    

   Last edited: Sep 19, 2005

   Stevecgz, Sep 19, 2005
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3. Sep 19, 2005 #2

   dextercioby

   

   Science Advisor

   Homework Helper

   Insights Author

   It's no big deal.
   
   [tex] \int \frac{\sin^{3}x}{\cos x} \ dx =\int \frac{\sin x \left(1-\cos^{2}x\right)}{\cos x} \ dx =\int \tan x \ dx -\int \sin x \ d\left(\sin x\right) = ... [/tex]
   
   Daniel.

    

   dextercioby, Sep 19, 2005
4. Sep 19, 2005 #3

   Stevecgz

   

   Thanks dextercioby, I understand it now.
   
   Steve

    

   Stevecgz, Sep 19, 2005

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