I need to find the green circle described in the picture below. (go from top left to bottom right)(adsbygoogle = window.adsbygoogle || []).push({});

The base values are:

the radius of the ball = d1 = 10

height down into the ball that forms the circle d2. h = 0.5.

I don't know if these values are useful in the end, but R on the right is sqrt(19)/2. which is the radius of the smaller circle, and also how far this circle is from the top. a way to visualize that is this picture.

[URL]http://upload.wikimedia.org/wikipedia/commons/5/56/Small_circle.svg[/URL]

from the formation of the equilateral triangle, a 90 degree angle is made, which finally forms a line that travels from that point of the ball to the bottom point of the ball, and finally back to where it is from.

so in the end, i am looking for the circumference of the green line on the ball. This was very hard to describe to, even to professors, which in the end couldn't help me, so I thought i would ALSO make a video of the problem!

http://www.youtube.com/watch?v=fCHQLQiLYUU"

The L in the video is wrong, it should be R, which would describe the same R as in the diagram!

Feel free to ask for more details, since even i don't think there might be enough information initially to figure this one out.

If you guys figure it out, i'll explain what this is used for! it's not just a purely mathematical exercise!

**Physics Forums | Science Articles, Homework Help, Discussion**

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Finding arbitrary circumference/circle on a sphere

Can you offer guidance or do you also need help?

Draft saved
Draft deleted

Loading...

Similar Threads for Finding arbitrary circumference |
---|

A Can I find a smooth vector field on the patches of a torus? |

I Arbitrariness of connection and arrow on sphere |

**Physics Forums | Science Articles, Homework Help, Discussion**