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a mass is distributed along a rod by the function M(X)= bx - a(x^2). The length of the rod is 3b/4a. What is the center of mass.

Ive tried working it out by using integrals to find the the total mass, and then divide it by 2, and then try to find out the x for that. The equation I used is

l= integral{ sqrt (1+ (dy/dx)^2) dx }

it came out with cosh and things like that, and I just can not find the x.

Help?