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Finding change in momentum

  1. Jun 6, 2009 #1
    1. The problem statement, all variables and given/known data

    Pitcher pitches a .30 kg softball has velocity 14 m/s at an angle of 36 degrees below the horizon just before the bat contacts the ball. What is the magnitude of change in momentum if the ball leaves the bat with a velocity of 23 m/s, vertically downward.

    2. Relevant equations

    v(i) = <14cos324, 14sin324> = <11, -4.3>
    v(f) = <23cos270, 23sin270> = <0, -23>
    Delta p = mv(f) - mv(i) = m [v(f) - v(i)]

    3. The attempt at a solution

    Delta p = .30(<0, -23> - <11, -4.3>) = <-3.3, -5.7>

    Magnitude of delta p = sqrt[(-3.3)^2 + (-5.7)^2] = 6.6
     
  2. jcsd
  3. Jun 6, 2009 #2

    LowlyPion

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    Homework Helper

    I'm not sure I follow your values for the components of the initial velocity.
    I get ...

    14 cosine36 = 11.34
    14 sine 36 = 8.23
     
  4. Jun 6, 2009 #3
    You're right...not sure how my brain froze for that calculation...must have been a typo...thought I double-checked it! Thanks!
     
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