# Finding closest distance

Dick
Homework Helper
Good luck!

HallsofIvy
Initially, B was "5 km to the south east" so B's initial position is $(5\frac{\sqrt{2}}{2}, 5\frac{\sqrt{2}}{2}$ ($sin(45^o)= \frac{\sqrt{2}}{2})$. Since B is moving straight North at 6 km/h, B's position at time t hours must be $(5\frac{\sqrt{2}}{2}, 5\frac{\sqrt{2}}{2}+ 6t)$). If $5\frac{\sqrt{2}}{2}= 3.53$(and it is) you are correct. Glad you don't have to quit school!