Hello, How do i find coefficient of friction knowing only mass, velocity and incline for a inclined plane?
How do you find the force that is needed to go up the hill at the same velocity?
You need to sum all the forces and get some equations to find mu. It would be easy if the cyclist was on flat land, then it would just be
But since he is on an incline you need to find the component of the gravitational force that is in the same direction as the normal force... and then plug that in to find [tex]\mu[/tex].
Edit: You need to know the inclination angle of the hill. I don't know if that was given to you or not.
Nasu, no i am not given an Fa.
All I have is: A biker rides up an 9.75degree hill at a constant speed of 5.95m/s. The biker and bicycle together have a mass of 98.7kg.
Find the coefficient..
What force does the system need to make the biker go up the hill at the same velocity..
What must the bikers power output be in order to go up the hill at the same speed.
Thanks guys I really appreciate it.
When the bike goes up the hill, the force that counteracts the weight component down the plane IS the static friction force between the rear tire and the road, which must be equal and opposite to the weight component down the plane. This is the only way a non-rocket powered vehicle can move ....if no friction, the wheels just spin in place. No matter what speed, this force is the same, but the power delivered by the cyclist will be different for different speeds. I don't see anything about the bike going down, you should post the question as written. You can't find the coefficient of friction, only the friction force, which I think it what the problem is asking for. Rolling and axle friction should be ignored, i guess.Sorry, my bad I re-wrote the question without it in front of me. It is going Down and it asks for the rest when it goes up. But how do i find the coefficient?
Sorry, my bad I re-wrote the question without it in front of me. It is going Down and it asks for the rest when it goes up. But how do i find the coefficient?
Thanks for clarifying the question. Your equation is incorrect, but you already answered part a in your post #6, so you must have done something right at that time. For part b, nasu has already given you some great hints in posts 14 and 18. Then move onto part c.umg = mgsin(theta ?
almost. The friction force is not umgsin theta...your geometry and trig is a bit off..,, it's umg (_?__)theta.I think i GOT the force required to go up the mountain. Can someone please verify?
Fa - Ff - F// = 0
Fa - umgsin(theta) - mgsin(theta) = 0
Solve for Fa.