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Hi there :)

At 19

I used the formula for linear expansion

change in L = Lx(coefficient of linear expansion)(change in temperature)

My attempt:

Steel's coefficient of linear expansion as given by my textbook: 11x10

So over the temperature range of 266 degrees (285 - 19), each centimetre would differ by about (266)(11x10

Multiplying by 20.18 gives 0.059

Taking this away from 20.18 gives: 20.1209

The change in length will now be: 20.12 - 20.08 = 0.04095

Subbing into the expansion formula:

0.04095 = (20.08)(285 - 19)(a)

a = 7.667x10

This is for an assignment, and I just want to see if I'm heading in the right direction

Thanks in advance

At 19

^{[tex]\circ[/tex]}C, a rod is exactly 20.08 cm long on a steel ruler. Both the rod and the ruler are placed in an oven at 285^{[tex]\circ[/tex]}C, where the rod now measures 20.18 cm on the same ruler. What is the coefficient of linear expansion for the material of which the rod is made?I used the formula for linear expansion

change in L = Lx(coefficient of linear expansion)(change in temperature)

My attempt:

Steel's coefficient of linear expansion as given by my textbook: 11x10

^{-6}So over the temperature range of 266 degrees (285 - 19), each centimetre would differ by about (266)(11x10

^{-6}) = 0.002926Multiplying by 20.18 gives 0.059

Taking this away from 20.18 gives: 20.1209

The change in length will now be: 20.12 - 20.08 = 0.04095

Subbing into the expansion formula:

0.04095 = (20.08)(285 - 19)(a)

a = 7.667x10

^{-6}This is for an assignment, and I just want to see if I'm heading in the right direction

Thanks in advance

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