A rocket is fired at an angle from the top of a tower of height 50.0m. Because of the designs of its engines, its position coordinates are of the form x(t)=A+Bt^2 and y(t)=C+Dt^3, where A, B, C, and D are constants. The acceleration of the rocket after 1.00s after firing is a= (4.00i+3.00j)m/s^2. Find the constants A, B, C, and D including their SI units. I took the derivative of the position vectors twice to get the acceleration vector and plugged in 1.00s into t to find D=0.500m/s^3 and B=2.00m/s^2. I am stuck on where to go after that to get A and C.