Finding conventional current

[laser123]

Pull a rectangular loop through a magnetic field
In the figure a rectangular loop of wire L = 15 cm long by h = 2 cm high, with a resistance of R = 0.8 ohms, moves with constant speed v = 5 m/s as shown. The moving loop is partially inside a rectangular region where there is a uniform magnetic field (gray area) and partially in a region where the magnetic field is negligibly small.

image: http://www.webassign.net/mi3/21.P.082-Fig20.92a.jpg

In the gray region, the magnetic field points into the page, and its magnitude is B = 1.7 tesla.



(c) What is the conventional current in the loop?


______A
(d) Which of the following are true? Check all that apply.
Because a current flows in the loop, there is a magnetic force on the loop.
The magnetic force only stretches the loop; the net magnetic force on the loop is zero.
The magnetic force on the loop is in the same direction as the velocity of the loop.

(e) What is the magnitude of the magnetic force on the loop?
________N


Thanks in advance.

 

[tiny-tim]

hi laser123!

show us what you've tried, and where you're stuck, and then we'll know how to help!

 

[laser123]

I'm stuck on C. I tried Fb=qvB then -Fb=qE then -Fb/q=E------->E*L=delta then deltaV/R=I

 

[tiny-tim]

I tried Fb=qvB then -Fb=qE then -Fb/q=E------->E*L=delta then deltaV/R=I

emf = Blv ?

 

[asteriatic]

I would like to provide the following response to the given content:

In this scenario, we are dealing with a rectangular loop of wire moving through a magnetic field. The loop has a length of 15 cm, a height of 2 cm, and a resistance of 0.8 ohms. The loop is moving at a constant speed of 5 m/s, with part of it inside a region with a uniform magnetic field and the other part in a region with a negligible magnetic field.

To find the conventional current in the loop, we can use the equation I = V/R, where I is the current, V is the voltage, and R is the resistance. In this case, the voltage can be calculated using the formula V = Bvl, where B is the magnetic field strength, v is the velocity of the loop, and l is the length of the part of the loop inside the magnetic field. Plugging in the given values, we get V = (1.7 T)(5 m/s)(0.15 m) = 1.275 V. Therefore, the conventional current in the loop is I = (1.275 V)/(0.8 ohms) = 1.594 A.

Moving on to the true statements, we can conclude that all three statements are correct. As there is a current flowing in the loop, there will be a magnetic force acting on the loop. The magnetic force will stretch the loop, but the net force on the loop will be zero, as the force acting on one side of the loop will be canceled out by the force acting on the opposite side. And finally, the magnetic force on the loop will be in the same direction as the velocity of the loop, as determined by the right-hand rule.

To calculate the magnitude of the magnetic force on the loop, we can use the equation F = BIl, where F is the force, B is the magnetic field strength, I is the current, and l is the length of the part of the loop inside the magnetic field. Plugging in the values, we get F = (1.7 T)(1.594 A)(0.15 m) = 0.407 N. Therefore, the magnitude of the magnetic force on the loop is 0.407 N.

In conclusion, by considering the given information and using the appropriate equations, we can determine the conventional current in the loop, the true statements about the magnetic force