- #1

notmetalenough

- 11

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I'm not quite sure how I'm supposed to be doing this problem.

Consider the circuit shown in the figure below.

R = 21.3 ohms

http://east.ilrn.com/graphing/bca/user/appletImage?dbid=411814203 [Broken]

Find the current in the 21.3 ohm resistor.

I combined (serial) R with the 5.85 ohm resistor, getting an equivalent resistance of 27.15 ohms. Then combined the middle (parallel) 11.7 and the other 5.85, getting an equivalent resistance of 3.9 ohms. Then I combined the 3.9 and the 27.15 as parallel resistors leaving me with a 3.41 ohm resistor and an 11.7 ohm resistor in series. which I added together to get a total resistance of 15.11 ohms.

I then divided the Voltage by the resistance to get the amount of current, and worked backwards applying it to each series part and then dividing it among the parallel components.

I ended up getting something along the lines of 0.283 A through the 21.3 resistor. Did I miss something somewhere? Did I combine these correctly?

Thanks

Consider the circuit shown in the figure below.

R = 21.3 ohms

http://east.ilrn.com/graphing/bca/user/appletImage?dbid=411814203 [Broken]

Find the current in the 21.3 ohm resistor.

I combined (serial) R with the 5.85 ohm resistor, getting an equivalent resistance of 27.15 ohms. Then combined the middle (parallel) 11.7 and the other 5.85, getting an equivalent resistance of 3.9 ohms. Then I combined the 3.9 and the 27.15 as parallel resistors leaving me with a 3.41 ohm resistor and an 11.7 ohm resistor in series. which I added together to get a total resistance of 15.11 ohms.

I then divided the Voltage by the resistance to get the amount of current, and worked backwards applying it to each series part and then dividing it among the parallel components.

I ended up getting something along the lines of 0.283 A through the 21.3 resistor. Did I miss something somewhere? Did I combine these correctly?

Thanks

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