- #1
Jennifer_ea
- 7
- 0
Homework Statement
We are given the following diagram:
And the values R1 = 13.0 Ω, R2 = 84.0 Ω, and R3 = 18.0 Ω
VAB = 110.0 V
I have previously solved for Req of 69.5 Ω
Homework Equations
V=IR
The Attempt at a Solution
I have found Req for the circuit to the right of A-B (992/11 Ω)
My first try I'm really not sure what I did but got 1 A. I must have made an error somewhere for that one.
For the second try I used the 1 A I got from... somewhere and found that the AB section is 48.2% of the load, and used 0.482 A for the answer. Basically I was flailing around and wasted my chances.
I only have one try left, and this is what I've done so far:
I searched around the forum and found information about this table method.
First I used the series way, having CD Req (R2) and leaving the two 13 Ω resistors (R1 and R3) closest to the beginning.
--| -R1- | --R2-- | --R3-- | T
--|-------|--------|--------|---------
E |2.246 | 7.511 | 2.246 | 12
I | 0.173 | 0.173 | 0.173 |
R| 13 ---| 43.5 -| 13 --- |
I then took the R2 section and split it into CD and Req for the circuit to the right and did it again for parallel
--| -CD- | --Req--- | T
--|---------|---------|--------
E |7.511 --| 7.511 -|
I | 0.0894 | 0.0839 | 0.173
R| --84 ---| 992/11 |
I think this gives me a current of 0.0894 A through CD, but I'm not confident I'm using these tables correctly. Am I allowed to combine like I have?
Thanks for your help!