- #1

Miike012

- 1,011

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I think the book is wrong.

Why is the current (which they denote I

Where V

In there equation they left out the the resistor of 20 ohmes

Why is the current (which they denote I

_{L}) equal to V_{s}/(R_{eq})Where V

_{s}= 458.3kV and R_{eq}is the equivalent resistance of the circuit equal to the sum of the two resistors in series ( R_{eq}= 220 + 20 = 240).In there equation they left out the the resistor of 20 ohmes