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I think the book is wrong.
Why is the current (which they denote I_{L}) equal to V_{s}/(R_{eq})
Where V_{s} = 458.3kV and R_{eq} is the equivalent resistance of the circuit equal to the sum of the two resistors in series ( R_{eq} = 220 + 20 = 240).
In there equation they left out the the resistor of 20 ohmes
Why is the current (which they denote I_{L}) equal to V_{s}/(R_{eq})
Where V_{s} = 458.3kV and R_{eq} is the equivalent resistance of the circuit equal to the sum of the two resistors in series ( R_{eq} = 220 + 20 = 240).
In there equation they left out the the resistor of 20 ohmes
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