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Finding Current of a Circuit

  1. Jul 16, 2008 #1
    1. The problem statement, all variables and given/known data
    A circuit consists of a 215 resistor and a 0.200 H inductor. These two elements are connected in series across a generator that has a frequency of 120 Hz and a voltage of 235 V.

    (a) What is the current in the circuit?

    (b) Determine the phase angle between the current and the voltage of the generator.


    2. Relevant equations
    Xl=2(pi)fL
    Irms=Vrms/Xl

    3. The attempt at a solution
    I used the equation to get 150.796 for Xl, then i plugged that into the equation Irms=Vrms/Xl to find current, but that gave me 1.558, which was not the right answer
     
  2. jcsd
  3. Jul 16, 2008 #2

    berkeman

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    Staff: Mentor

    Your second equation in #2 above is incomplete. The resistor and inductor are in series, so you must use their total impedance in the V = I * Z equation. Does that fix it for you?
     
  4. Jul 16, 2008 #3
    I'm still not getting it. I used V=IZ. I have V, which is 235 volts right? still, i did not have I or Z. So i used Z=(square root of)R^2 +(Xl-Xc)^2, and I got .89 for Z. Then plugging back into V=IZ, (235v)=I(.89)=262.49A for current?
     
  5. Jul 17, 2008 #4

    alphysicist

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    Homework Helper

    Hi kdrobey,

    For these series RLC problems the impedance is

    [tex]
    Z=\sqrt{R^2 + (X_L - X_C)^2}
    [/tex]

    and so the impedance cannot be smaller than the resistance, so something is wrong there. What were the actual numbers you used to calculate Z?
     
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