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Introductory Physics Homework Help
Finding distance -- Find the height of an object given ratio of two distances
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[QUOTE="D.Man Hazarika, post: 4991710, member: 539300"] [h2]Homework Statement [/h2] A body is dropped from certain height H. If the ratio of the distances traveled by it in (n-3) seconds to (n-3)rd second is 4:3, find H (take g= 10 m/s²) (answer: 125m) [h2]Homework Equations[/h2][h2]The Attempt at a Solution[/h2] I did this way but I came to a dead end... To find H, s= 1/2 gt² = 1/2 * 10 * (n-3)² = 5*(n²-9) = 5n²+45...(I) S nth = u+g/2(2n-1) = 5(2n-1) = 10n-5...(II) equating (I) AND (2) 5n²+45= 4 ________ ___ 10n-5. 3 => 3(5n²+45)=4(10n-5) => 15n²+135=40n-20 => 15n²-40n=-20-135 => 15n²-40n=-155 => 15n²+155=40n => 15n²+155= 40 ____________ n This is a dead end...what should I do next...? [/QUOTE]
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Introductory Physics Homework Help
Finding distance -- Find the height of an object given ratio of two distances
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