# Finding distance that a pad is compressed after being dropped

## Homework Statement

An egg is dropped from a third-floor win-
dow and lands on a foam-rubber pad without
breaking.
The acceleration of gravity is 9.81 m/s2 .
If a 56.3 g egg falls 11.9 m from rest and the
7.29 cm thick foam pad stops it in 6.32 ms,
by how much is the pad compressed? Assume
constant upward acceleration as the egg com-
presses the foam-rubber pad. (Assume that
the potential energy that the egg gains while
the pad is being compressed is negligible.)

## Homework Equations

I'm not quite sure. I was thinking EP (mgh) = 1/2 kx2, but you aren't given the spring constant.

## The Attempt at a Solution

I calculated that just before the egg hit the pad, its velocity was 15.28m/s. After this...I have no clue where to go.

I think you probably have to do something with the impulse that the pad delivers to the egg:
The egg hits the pad with some initial velocity and then is brought to a complete stop before most likely bouncing up a little bit.
This is essentially an acceleration in the upward direction. Then you can use the equations:
d(x)=v(int)t=1/2at^2
v(final)=v(int) + at
to solve for your two unknowns.
Hope this helps, sorry my equations are not that easy to read (d=delta)

I think my brain is fried after doing physics for a few hours straight...but your first equation doesn't seem to make sense to me.

d(x)=v(int)t=1/2at^2

Two equals signs? How would you solve for x?

haha sorry the second equals was supposed to be a plus. my bad. Yea solving for x would have been interesting.

Tried that, got an answer of .144854 m, but according to my online assignment page, that's wrong. Is there a problem in my math, or is that the wrong formula to use?