- #1

mr_coffee

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At each point on the surface of the cube shown in Figure 23-27, the electric field is parallel to the z axis. The length of each edge of the cube is 4.0 m. On the top face of the cube E = -40 k N/C, and on the bottom face of the cube E = +29 k N/C. Determine the net charge contained within the cube.

Image: here

Flux = (29E3 N/C)(4.0)^2;

Flux = 464000 k going up

Flux = (-40E3 N/C)(4.0)^2;

Flux = -640000 k going down

Net Flux = -640000 + 464000 = -176000

I submitted it and was inncorrect,

So i tried added them together and i got 1.104E6, that's the flux, now I found an equation that says, Flux = Qtotal/Eo, so I took Flux*Eo = Qtotal and got 9.7704E-6 and it is still wrong!

Image: here

Flux = (29E3 N/C)(4.0)^2;

Flux = 464000 k going up

Flux = (-40E3 N/C)(4.0)^2;

Flux = -640000 k going down

Net Flux = -640000 + 464000 = -176000

I submitted it and was inncorrect,

So i tried added them together and i got 1.104E6, that's the flux, now I found an equation that says, Flux = Qtotal/Eo, so I took Flux*Eo = Qtotal and got 9.7704E-6 and it is still wrong!

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