What is the value of F_max for an impulse of 6.8 Ns in the given figure?

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In summary, the problem asks for the value of F_max that would result in an impulse of 6.8 Ns. Two attempts were made, first using the integral of F with respect to time, and then using the area of a triangle. However, both attempts were incorrect due to not considering the units on the time axis, which are in milliseconds. The correct answer is F_max=1700N.
  • #1
krej
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Homework Statement


In the figure , what value of F_max gives an impulse of 6.8 Ns?
http://img76.imageshack.us/img76/1782/09ex05.jpg

Homework Equations


Integral of F with respect to time equals impulse


The Attempt at a Solution


I tried doing two things, and they were both wrong.

First, i tried the integral of F with respect to time from 0 to 8 = 6.8.
Ft from 0 to 8 = 6.8
F(8) - F(0) = 6.8
F = 6.8/8
F = 0.85
I realize that is wrong though, since the picture they give us isn't of constant force.

So then I tried using the area of a triangle:
Area = (1/2)b*h
Area = (1/2)*8*h
4h = 6.8
h = 6.8/4 = 1.7

So I entered 1.7 into the website, and it said it was wrong. If that didn't work, I have no idea what else I could do to find it.
 
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  • #2
krej said:

Homework Statement


In the figure , what value of F_max gives an impulse of 6.8 Ns?
http://img76.imageshack.us/img76/1782/09ex05.jpg

Homework Equations


Integral of F with respect to time equals impulse


The Attempt at a Solution


I tried doing two things, and they were both wrong.

First, i tried the integral of F with respect to time from 0 to 8 = 6.8.
Ft from 0 to 8 = 6.8
F(8) - F(0) = 6.8
F = 6.8/8
F = 0.85
I realize that is wrong though, since the picture they give us isn't of constant force.

So then I tried using the area of a triangle:
Area = (1/2)b*h
Area = (1/2)*8*h
4h = 6.8
h = 6.8/4 = 1.7

So I entered 1.7 into the website, and it said it was wrong. If that didn't work, I have no idea what else I could do to find it.
Note that the units on the time axis are miliseconds. Hence, 4x10^-3*Fmax==6.8, Fmax==1700N.
 
Last edited by a moderator:
  • #3
Oh, wow I didn't notice that at all. I'm too used to it always being in seconds I didn't even think about looking at that. :p

Thanks a lot for your help!
 

1. What is "f_max" in relation to an impulse signal?

The term "f_max" refers to the maximum frequency present in an impulse signal. This is the highest frequency component that can be observed in the signal.

2. How do you find the f_max of an impulse signal?

To find the f_max of an impulse signal, you can use Fourier analysis techniques such as the Fast Fourier Transform (FFT) to convert the signal from the time domain to the frequency domain. The highest peak in the frequency spectrum will correspond to the f_max of the impulse signal.

3. Can the f_max of an impulse signal change over time?

No, the f_max of an impulse signal does not change over time. It is a characteristic of the signal and is determined by the highest frequency component present in the signal.

4. What factors can affect the f_max of an impulse signal?

The f_max of an impulse signal can be affected by the bandwidth and duration of the signal. A wider bandwidth will result in a higher f_max, while a longer duration may result in a lower f_max.

5. Why is it important to find the f_max of an impulse signal?

Finding the f_max of an impulse signal is important in understanding the frequency content of the signal. It can also be used in various applications such as signal processing and filtering, where knowledge of the highest frequency component is necessary.

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